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Science Physics Formulas

Problem:

Solve for time with the quadratic square root being subtracted.
time

Inputs:

initial vertical velocity (vy0)
acceleration of gravity (g)
vertical displacement at time (Δy)
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Conversions:

initial vertical velocity (vy0)
= 0
= 0
meter/second
acceleration of gravity (g)
= 0
= 0
meter/second^2
vertical displacement at time (Δy)
= 0
= 0
meter

Solution:

time (t)
= NOT CALCULATED

Other Units:

Change Equation or Formulas:

Tap or click to solve for a different unknown or equation
vertical velocity
vertical velocity at timevertical velocity at time
initial vertical velocityinitial vertical velocity
acceleration of gravityacceleration of gravity
timetime
vertical displacement
vertical displacement at timevertical displacement at time
initial vertical velocityinitial vertical velocity
timetime - quadratic square root added
timetime - quadratic square root subtracted
acceleration of gravityacceleration of gravity
horizontal velocity
horizontal velocity at timehorizontal velocity at time
horizontal displacement
horizontal velocity at timehorizontal velocity at time
initial horizontal velocityinitial horizontal velocity
timetime
Range given projection angle and
equal initial and final elevations
rangerange
initial velocityinitial velocity
acceleration of gravityacceleration of gravity

References - Books

Tipler, Paul A.. 1995. Physics For Scientists and Engineers. Worth Publishers. 3rd ed.
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