Unsteady State Heat Transfer Dimensionless Value
Problem:
Solve for Biot number.
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| Biot Number |
| heat transfer coefficient |
| characteristic length |
| thermal conductivity |
References - Books:
Lindeburg, Michael R. 1992. Engineer In Training Reference Manual. Professional Publication, Inc. 8th Edition.
Background
The Biot number (Bi) is a dimensionless quantity used extensively in heat transfer calculations. Named after the French physicist Jean-Baptiste Biot, this number provides significant insights into the heat conduction and convection processes. The Biot number compares the internal resistance to heat conduction within a body to the external resistance to heat convected from its surface. This comparison is crucial in determining whether the temperature within a body can be assumed uniform (lump system approach) or if temperature gradients must be considered.
Equation
The Biot number is defined using the following equation:
Bi = hL / ks
where:
- h is the heat transfer coefficient (W/m²·K)
- L is the characteristic length (m)
- ks is the object's thermal conductivity (W/m·K).
Depending on the medium and materials involved, an alternative form using thermal conductivity (ks) of the surrounding fluid or material may be used in some contexts.
How to Solve
Solving the Biot number involves:
- Identify the heat transfer coefficient (h): This is typically given or can be determined based on the conditions around the object (such as fluid velocity, temperature differences, etc.).
- Determine the characteristic length (L): The characteristic length is often calculated based on geometry, such as the object's volume divided by the surface area for three-dimensional bodies.
- Establish the thermal conductivity (ks): The material's thermal conductivity must be known or obtained from material property tables.
- Apply the Biot equation: Insert the values into the Biot equation to obtain the dimensionless Biot number. Bi = hL / ks
Example
Let's consider a sphere with the following parameters:
Heat transfer coefficient of h = 50 W/m²·K
Diameter of the sphere of D = 0.1 m
Thermal conductivity of ks = 200 W/m·K
The characteristic length for a sphere (typically the radius) L = D / 2 = 0.05 m
Plugging the values into the Biot equation:
Bi = 50 W/m²·K x 0.05 m / 200 W/m·K
Bi = 2.5 / 200
Bi = 0.0125
This low Biot number implies a minimal temperature gradient within the sphere, validating the lumped capacitance model.
Fields/Degrees Where It Is Used
- Mechanical Engineering: Solving heat transfer problems in engines, turbines, and machinery components.
- Chemical Engineering: Heat transfer is crucial in reactor design and analysis.
- Civil Engineering: In evaluating heat flow through building materials for energy efficiency.
- Aerospace Engineering: Critical in analyzing thermal protection systems and materials tolerating extreme temperatures.
- Environmental Engineering: Used in modeling thermal processes in environmental systems, including soil heat flux and aquatic systems' thermal behavior.
Real-Life Applications
- Design of Heat Exchangers: Ensure that heat transfer effectiveness is optimized while maintaining the structural integrity of the materials.
- Thermal Analysis of Electronics: Cooling mechanisms in electronic devices to prevent overheating.
- Medical Device Manufacturing: Control thermal conditions in devices such as incubators and sterilizers.
- Construction Industry: Insulation design for buildings to effectively manage heat loss/gain.
- Automotive Industry: Enhancing engine cooling systems for better performance and efficiency.
Common Mistakes
- Incorrect Characteristic Length: Using incorrect geometry leads to erroneous Biot number calculations.
- Ignoring Material Anisotropy: Not accounting for directional thermal conductivity variations.
- Overlooking Convection Coefficient Variations: Assuming a constant convection coefficient when conditions change significantly.
- Assuming Lumped Capacitance Applicability: Misusing it in systems with significant internal temperature gradients Bi > 0.1.
- Misidentifying Fluid Dynamics Influence: Neglecting the effects of fluid movement around the object affecting h.
Frequently Asked Questions
- Q: What is the significance of a high Biot number?
A: A high Biot number (>>1) indicates that thermal resistance within the object is much higher than surface convection resistance, leading to significant internal temperature gradients.
- Q: When can the lumped capacitance method be applied?
A: It is valid when the Biot number is less than 0.1, implying that internal conduction resistance is much lower than surface convection resistance, resulting in negligible temperature gradients within the object.
- Q: How is the characteristic length determined for irregular shapes?
A: The volume ratio to the surface area or other geometrically appropriate dimensions can approximate the characteristic length for irregular shapes.
- Q: What does a Biot number of 1 signify?
A: A Biot number of 1 suggests that the internal and external thermal resistances are comparable, necessitating a more detailed analysis of conduction and convection effects.
- Q: Can the Biot number be negative?
A: No, the Biot number is always a non-negative value as it represents a ratio of positive thermal resistances.