Gravitational Acceleration Calculator

Gravitational acceleration g toward central mass M
Acceleration equals G times mass divided by radius squared

Solution

Share:

How It Works

Gravitational acceleration is the acceleration any free-falling object experiences at distance r from a massive body of mass M: g = GM / r², where G = 6.6743 × 10⁻¹¹ N·m²/kg² is the universal gravitational constant. The formula comes directly from Newton's law of gravitation divided by the test mass — that's why all objects fall with the same g regardless of their own mass (Galileo's principle of equivalence). This calculator solves the equation for any one of three unknowns — acceleration, radius, or central mass — given the other two.

Example Problem

Calculate Earth's surface gravitational acceleration. Earth's mass is M = 5.972 × 10²⁴ kg and its mean radius is r = 6.371 × 10⁶ m.

  1. Write the gravitational acceleration formula: g = G × M / r².
  2. Compute the numerator: G × M = (6.6743 × 10⁻¹¹) × (5.972 × 10²⁴) ≈ 3.986 × 10¹⁴ m³/s².
  3. Compute the denominator: r² = (6.371 × 10⁶)² ≈ 4.058 × 10¹³ m².
  4. Divide: g = 3.986 × 10¹⁴ / 4.058 × 10¹³ ≈ 9.82 m/s².
  5. Compare to the standard reference value g₀ = 9.80665 m/s² — the tiny excess comes from rounding Earth's radius and mass; local variations from latitude, altitude, and density anomalies cause the actual surface g to range from about 9.78 to 9.83 m/s².

Key Concepts

Gravitational acceleration g depends only on the source mass M and the distance r — never on the falling object's own mass. The inverse-square fall-off is steep: at 400 km altitude (ISS), g drops to ≈ 8.7 m/s², about 89% of surface value, which is why astronauts inside the ISS experience apparent weightlessness as the station continuously free-falls around Earth. Other planets give very different values: the Moon's surface gravity is 1.62 m/s² (about 1/6 of Earth's), Mars 3.71 m/s², Jupiter 24.79 m/s², and the Sun a crushing 274 m/s². Use this calculator to find g on any body or to invert the formula and estimate a planet's mass from its measured surface gravity.

Applications

  • Aerospace engineering: computing local g for spacecraft trajectory simulations and reentry calculations.
  • Geophysics: measuring tiny variations in surface g to map subsurface density (oil, mineral, and groundwater exploration).
  • Astronomy: estimating planetary masses from observed surface gravity or from satellite orbital data.
  • Physics education: demonstrating that g = GM/r² produces the familiar 9.81 m/s² from first principles.
  • Lunar and Martian mission planning: setting equipment weight budgets based on each body's surface gravity.

Common Mistakes

  • Confusing the universal constant G (6.6743 × 10⁻¹¹ N·m²/kg², constant everywhere) with the local gravitational acceleration g (≈ 9.81 m/s² at Earth's surface, varies with location).
  • Using altitude instead of distance from the planet's center for r — the formula needs the full center-to-center distance, not the height above the surface.
  • Assuming g is constant with altitude — it actually decreases as 1/r², so satellites in high orbits experience much less gravity than at sea level.
  • Forgetting that on a planet's surface, r is the planet's radius — not zero — because gravitational acceleration is computed at the center-of-mass distance.
  • Mixing mass and length units (e.g., kilograms with kilometers) without converting to SI — the formula returns m/s² only when M is in kg and r is in meters.

Frequently Asked Questions

How do you calculate gravitational acceleration?

Apply the formula g = G × M / r², where G = 6.6743 × 10⁻¹¹ N·m²/kg² is the universal gravitational constant, M is the mass of the central body in kilograms, and r is the distance from that body's center in meters. The result g comes out in m/s².

What is the formula for gravitational acceleration?

g = G × M / r², where G is the universal gravitational constant, M is the mass of the body creating the gravity, and r is the distance from its center. This is the local gravitational acceleration felt at any point r away from a mass M.

Why is gravity 9.81 m/s² on Earth?

Substituting Earth's mass (5.972 × 10²⁴ kg) and mean radius (6.371 × 10⁶ m) into g = GM/r² gives approximately 9.82 m/s². The standard reference value 9.80665 m/s² is a defined average that accounts for Earth's oblateness, rotation, and local density variations.

Does gravitational acceleration depend on the falling object's mass?

No. The formula g = GM/r² shows g depends only on the central body's mass M and the distance r — not on the falling object. This is why a feather and a hammer fall at the same rate in vacuum on the Moon, a result demonstrated by Apollo 15 astronauts in 1971.

How does gravitational acceleration change with altitude?

It falls off as the inverse square of the distance from the planet's center. At the ISS's 400 km altitude (r ≈ 6,771 km), g ≈ 8.7 m/s² — about 89% of the surface value. At geostationary altitude (~36,000 km), g drops to about 0.22 m/s².

What is gravitational acceleration on other planets?

Moon: 1.62 m/s² (about 1/6 of Earth's). Mars: 3.71 m/s². Venus: 8.87 m/s². Jupiter (cloud tops): 24.79 m/s². Sun: 274 m/s². Use this calculator with each body's mass and radius to verify these values.

References:

Lindeburg, Michael R. 1992. Engineer In Training Reference Manual. Professional Publication, Inc. 8th Edition.

Gravitational constant G: NIST CODATA. https://physics.nist.gov/cgi-bin/cuu/Value?bg

Standard acceleration of gravity: NIST CODATA. https://physics.nist.gov/cgi-bin/cuu/Value?gn

Worked Examples

Planetary Science

What is the surface gravity of Mars from its mass and radius?

Mars has a mass of 6.4171 × 10²³ kg and a mean radius of 3.3895 × 10⁶ m. Surface gravity controls how heavy a kilogram weighs there — and how much thrust a Mars rover or human habitat needs to plan for.

  • Knowns: M = 6.4171 × 10²³ kg, r = 3.3895 × 10⁶ m
  • G = 6.6743 × 10⁻¹¹ N·m²/kg²
  • g = G × M / r²
  • g = 6.6743 × 10⁻¹¹ × 6.4171 × 10²³ / (3.3895 × 10⁶)²
  • g = 4.282 × 10¹³ / 1.149 × 10¹³

g ≈ 3.727 m/s²

About 38% of Earth's 9.81 m/s². A 70 kg astronaut would weigh ≈ 261 N (≈ 59 lbf) on Mars vs 687 N on Earth — close to NASA's published Mars surface gravity of 3.71 m/s² (the small gap is the planet's equatorial bulge and rotation).

Gas Giant Astronomy

What gravity would an aircraft "feel" at Jupiter's cloud-top radius?

Jupiter has M ≈ 1.898 × 10²⁷ kg and an equatorial radius R ≈ 7.1492 × 10⁷ m at the 1-bar cloud tops (Jupiter has no real "surface"). This is the gravitational pull a probe like Galileo experiences as it enters the atmosphere.

  • Knowns: M = 1.898 × 10²⁷ kg, r = 7.1492 × 10⁷ m
  • G = 6.6743 × 10⁻¹¹ N·m²/kg²
  • g = G × M / r²
  • g = 6.6743 × 10⁻¹¹ × 1.898 × 10²⁷ / (7.1492 × 10⁷)²
  • g = 1.267 × 10¹⁷ / 5.111 × 10¹⁵

g ≈ 24.79 m/s²

Roughly 2.53× Earth's gravity. Combined with extreme winds (≈ 150 m/s) and crushing pressure below the cloud deck, this is why Galileo's entry probe survived only ~58 minutes before being destroyed at the 23-bar level.

Satellite Orbits

How weak is Earth's gravity at geostationary altitude?

Geostationary satellites orbit at r ≈ 4.2164 × 10⁷ m from Earth's center (≈ 35,786 km altitude). For station-keeping calculations and reaction-wheel sizing, engineers need to know the local g at that distance.

  • Knowns: M = 5.972 × 10²⁴ kg, r = 4.2164 × 10⁷ m
  • G = 6.6743 × 10⁻¹¹ N·m²/kg²
  • g = G × M / r²
  • g = 6.6743 × 10⁻¹¹ × 5.972 × 10²⁴ / (4.2164 × 10⁷)²
  • g = 3.985 × 10¹⁴ / 1.778 × 10¹⁵

g ≈ 0.2241 m/s²

About 1/44 of surface gravity. That's still strong enough to make GEO a useful Lagrange-free anchor for communications: gravity exactly balances the centripetal demand v²/r at the geosynchronous orbital speed (≈ 3.07 km/s).

Gravitational Acceleration Formula

Gravitational acceleration is the local g a small test mass feels at distance r from a body of mass M. It comes from dividing Newton's law of universal gravitation by the test mass, so g depends only on the source body and the distance to it — not on what is being attracted.

g = G × M / r²

Where:

  • g — gravitational acceleration at distance r (m/s²)
  • G — Newton's universal gravitational constant, 6.6743 × 10⁻¹¹ N·m²/kg²
  • M — mass of the gravitating body (kg)
  • r — distance from the body's center of mass to the point of interest (m); equal to the planet's radius for surface gravity

The inverse-square falloff means that doubling the distance quarters g. The formula models the source body as a point mass (or, equivalently, a spherically symmetric mass distribution outside its surface). It does not include centrifugal effects from rotation, latitude variations, or local density anomalies — published surface gravities for Earth (9.81 m/s²) and other planets average these in.

Surface Gravity of Planets

NASA-published surface gravity for the Sun, Moon, and the inner planets, alongside each body's mass and mean radius. Click a row to load that body's mass and radius into the calculator and solve for its surface gravity with g = G × M / r². For the complete list of all solar-system bodies with escape velocity, see the planetary data reference.

BodyMass (kg)Mean radius (km)Surface gravity (m/s²)Source
Sun1.99×10³⁰696,000274NASA Planetary Fact Sheet
Mercury3.3×10²³2,4403.7NASA Planetary Fact Sheet
Venus4.87×10²⁴6,0528.87NASA Planetary Fact Sheet
Earth5.97×10²⁴6,3719.807NASA Planetary Fact Sheet
Moon7.34×10²²1,7371.62NASA Planetary Fact Sheet
Mars6.42×10²³3,3903.71NASA Planetary Fact Sheet
Jupiter1.9×10²⁷69,91124.79NASA Planetary Fact Sheet
Saturn5.68×10²⁶58,23210.44NASA Planetary Fact Sheet

The listed surface gravity is NASA's published effective value, which includes the contribution of rotation and uses the equatorial radius. Computing g = G × M / r² directly from the listed mass and mean radius differs by a few percent for the fast-rotating gas and ice giants (Saturn's mean-radius g is about 11 m/s² vs the published 10.44 m/s²), and matches closely for the slowly-rotating rocky bodies.

Related Calculators

Related Sites